Question

the population of a town is increasing at the rate of 10% per annum what will be the population of a town at this rate after 2 years if the present population is 4200 0

Answer 1

$we \: know \: that.... \\ \\ p(1 + \frac{r}{100} ) \\ p = 42000 \\ r = 10\% \\ n = 2 \: year \\ p(1 + \frac{r}{100} ) \\ = 42000( {1 + \frac{10}{100} }^{2} ) \\ = 42000 \times \frac{110}{100} \times \frac{110}{100} \\ = 420 \times 11 \times 11 \\ = 420 \times 121 \\ = 50820 \\ answer.....50820$
after 2 year population is 50820...people