The population of a town is increasing at the rate of 5% per annum. if the present population is 44,100, then what was the populatin 2 years ago? also find population after one year
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if there is 5% increase in population every year then there will be 5% decrease in population every year.
By ci method:
P=44,100
T=2yrs
R=5%
A=P(1-R/100)^T
=44100(1-5/100)^2
=44100(1-1/20)^2
=44100(20-1/20)^2
=44100(19/20)^2
=44100*19/20*19/20
POPULATION BEFORE 2YRS=39800
P AFTER 1 YEAR WILL BE
BY SI METHOD:
SI=P*R*T/100
=44100*5*1/100
=2205
A=P+SI
=44100+2205
POPULATION AFTER 1YR=46305
mARK AS bRAINLEST
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5%is increases every year
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