the population of a town is increasing at the rate of 8 percent per annum what will be the population after two years if the present population is 12,500
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population after two years = 14580
step by step explanation:
present population of a town (p) == 12500
rate of increase (r) == 8% per annum
Time (t) == 2 years
conversion period = n= 2
population after 2 years
= P ( 1 + R/100 ) ^n
= 12500. ( 1 + 8/100 )^2
= 12500. ( 1 + 2/25 )^2
= 12500. ( 25 + 2 /25 ) ^ 2
= 12500. (27/25)^ 2
= 12500. (27/25) x 27/25
=14580
therefore
population after 2 years = 14580
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