Math, asked by kunal41687, 11 months ago

the population of a town is increasing at the rate of 8 percent per annum what will be the population after two years if the present population is 12,500

Answers

Answered by Hinalbhogesra
4

Answer:

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Answered by Anonymous
3

Answer:

population after two years = 14580

step by step explanation:

present population of a town (p) == 12500

rate of increase (r) == 8% per annum

Time (t) == 2 years

conversion period = n= 2

population after 2 years

= P ( 1 + R/100 ) ^n

= 12500. ( 1 + 8/100 )^2

= 12500. ( 1 + 2/25 )^2

= 12500. ( 25 + 2 /25 ) ^ 2

= 12500. (27/25)^ 2

= 12500. (27/25) x 27/25

=14580

therefore

population after 2 years = 14580

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