Math, asked by pooja330, 1 year ago

the population of a town is increasing at the rate of 8% per annum.What will be the population of the town after two years if the present population is 12500

Answers

Answered by mysticd
13

Answer:

\red { Population \: after \: 2\: years}\green {= 14580}

Step-by-step explanation:

 Present \: population \: of \:a \:town(p) = 12500

Rate \: of \: increase (r) = 8\% \: per\: annum

 Time (t) = 2 \: years

 conversion \:period = n = 2

 Population \: after \: 2\: years\\ = p\left( 1+\frac{R}{100}\right)^{n}

 = 12500\left( 1 + \frac{8}{100}\right)^{2}

 = 12500\left( 1 + \frac{2}{25}\right)^{2}

 = 12500\left(  \frac{25+2}{25}\right)^{2}

 = 12500\left(  \frac{27}{25}\right)^{2}

 = 12500\left(  \frac{27}{25}\right)\times \frac{27}{25}

 = 14580

Therefore.,

\red { Population \: after \: 2\: years}\green {= 14580}

•••♪

Answered by Arti123498
6

Answer:

hope this will help you

Attachments:
Similar questions