Question

the population of a town is increasing at the rate of 8% per annum.What will be the population of the town after two years if the present population is 12500

Answer 1

Answer:

$\red { Population \: after \: 2\: years}\green {= 14580}$

Step-by-step explanation:

$Present \: population \: of \:a \:town(p) = 12500$

$Rate \: of \: increase (r) = 8\% \: per\: annum$

$Time (t) = 2 \: years$

$conversion \:period = n = 2$

$Population \: after \: 2\: years\\ = p\left( 1+\frac{R}{100}\right)^{n}$

$= 12500\left( 1 + \frac{8}{100}\right)^{2}$

$= 12500\left( 1 + \frac{2}{25}\right)^{2}$

$= 12500\left( \frac{25+2}{25}\right)^{2}$

$= 12500\left( \frac{27}{25}\right)^{2}$

$= 12500\left( \frac{27}{25}\right)\times \frac{27}{25}$

$= 14580$

Therefore.,

$\red { Population \: after \: 2\: years}\green {= 14580}$

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Answer 2

Answer:

hope this will help you