Question

the population of a town is increasing at the rate of 8% per annum what will be the population of the town after 2 years if the present population is 12500

Answer 1

Answer:

Step-by-step explanation: please see the attachment

Ans is 14580

Answer 2

Answer: 14,580

Step-by-step explanation:

The exponential growth equation is given by :-

$y=A(1+r)^x$ , where A is initial amount , r is rate of growth and x is time period.

Given : Rate : r= 8% = 0.08

Present population = 12500

Time period : x=2 years

Then, the  population of the town after 2 years :-

$y=12500(1+0.08)^2\\\\\Rightarrow\ y=12500(1.08)^2=12500(1.1664)\\\\=14580$

Hence, the population of the town after 2 years = 14,580