the population of a town is increasing at the rate of 8% per annum what will be the population of the town after 2 years if the present population is 12500
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Answered by
13
Solution :
Population after 2 years =12500×(1+8100)2=12500×(1+8100)2
=12500×(108100)2=12500×(108100)2
=12500×2725×2725×2725=12500×2725×2725×2725
=14580=14580
Answer : 14580
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Population after 2 years =12500×(1+8100)2=12500×(1+8100)2
=12500×(108100)2=12500×(108100)2
=12500×2725×2725×2725=12500×2725×2725×2725
=14580=14580
Answer : 14580
please mark me as brain list plz........
apoorva320:
thank you
Answered by
3
Answer:14,500
Step-by-step explanation:
In this we should find the answer like finding the answer of amount
In this 8% would be the rate[R],2 years would be the time[T] and 12500 would be the principal amount[P].......
Interest=P×T×R/100
=12500×2×8/100....Here 2 0s can be cancelled making
125×2×8
=125×16
=2000.....here we have found the interest....
Next we should find the amount by adding the interest to the principal amount....that is....12500+2000=14500
Thus the population of the town would be 14,500 after 2 years in the rate of 8% with 2000 as interest....
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