Math, asked by apoorva320, 1 year ago

the population of a town is increasing at the rate of 8% per annum what will be the population of the town after 2 years if the present population is 12500

Answers

Answered by adrain123
13
Solution :

Population after 2 years =12500×(1+8100)2=12500×(1+8100)2

=12500×(108100)2=12500×(108100)2

=12500×2725×2725×2725=12500×2725×2725×2725

=14580=14580

Answer : 14580


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Answered by vinodpattar75
3

Answer:14,500


Step-by-step explanation:

In this we should find the answer like finding the answer of amount

In this 8% would be the rate[R],2 years would be the time[T] and 12500 would be the principal amount[P].......

Interest=P×T×R/100

=12500×2×8/100....Here 2 0s can be cancelled making

125×2×8

=125×16

=2000.....here we have found the interest....

Next we should find the amount by adding the interest to the principal amount....that is....12500+2000=14500

Thus the population of the town would be 14,500 after 2 years in the rate of 8% with 2000 as interest....

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