Question

The population of a town of India was 200000 in 2009, it increased to

266200 in 2012. Find the rate at which the population is increasing​

Answer 1

Step-by-step explanation:

Amount = P(1+ R/100)n

266200= 200000(1 + R/100)3

266200/200000 = (1 + R/100) 3

1331/ 1000 = (1/1 + R/100)3

(11/10) raise to power 3 = ( 1/1 + R/100)raise to power 3

11/10 = (1/1 + R/100)

11/10 - 1/1 = R/100

11-10/10 = R/100

1/10 = R/100

cross multiplication

10× R = 100×1

R = 100×1/ 10

R= 10% answer

hope you're satisfied with my answer

Answer 2

Answer:

thanks a lot for giving me thanks