Question

The population of a town three years ago was 'b' and the population of the town three years from now will be 'c'. what is the current population of the town, if it grows at the same rate?

Answer 1

3ago was-b
3years from now will be - c
a

Answer 2

Answer:

√bc

Step-by-step explanation:

let current population of town is x and growing at the rate of r% per annum

as given

population of town was three years ago = b

$\frac{x}{(1+\frac{r}{100})^{3}}=b\\\\=(1+\frac{r}{100})^{3}=\frac{x}{b} </p><p>$

and population of town after three years = c

$</p><p> x(1+\frac{r}{100})^{3} =c\\\\=(1+\frac{r}{100})^{3}=\frac{c}{x} </p><p>$

by comparing both the equation, we get

x²=bc

⇒x=√bc

so the current population of town is √bc.