Question

the population of a town was 150000 three years ago . It increases by 2%,5% and 8% in the last three years. what is the present population of the town?

Answer 1

p = 15000, R= 2%,5%,8%
T= 3years
present population = p(1+R/100)(1+R/100)(1+R/100)
15000×(1+2/100)(1+5/100)(1+8/100)

15000×51/50×21/20×27/25

3×51×27×21÷5 = 17350.2 Ans

Answer 2

Answer:

Step-by-step explanation:

P0

= 150000, R1

= 2%, R2

= 5%, R3

= 8%, P = ?,

T = 3 years

Present population

P = 1 2 3

0 1 1 1

100 100 100

R R R

P

               

= 150000 

2 5 8 1 1 1

100 100 100

     

              

= 150000 

1 1 2 1 1 1

50 20 25

     

              

= 150000 

51 21 27

50 20 25

 

P = 173502