The population of a town was 16000 three years ago. If it had increased by 3%, 2.5% and 5% in the last three years, find the present population of the town.
Answers
Answer:
Step-by-step explanation:
3 years ago ,the population of the town was 16,000
In one year,it increased by 3% ,therefore you find 3% of 16,000 ,which is = 480. Then add it to 16,000 =16,480
Then in the second year ,it increased by 2.5 % .So we find 2.5 % of 16,480,which is = 412.Then once again we add 412 to 16,480 =16,892
Then in the third year ,the population increased by 5% ,and 5 % of 16,892 = 844.6 ( At this point ,I doubt my answer because of the decimal point,but nevertheless it might still be right !!)
So the final answer should be 16,892 + 844.6 = 17,736.6 (which can be rounded up to 17,737 ...
.
.
.
.
.
Hope this helps !!
Answer:
17,736.6
Step-by-step explanation:
The population before 3 years ago =16,000
Given data,
In last three years population increased by 3%, 2.5% and 5%.
Therefore,
2 Years Before
Population = 16000 × 103
100
= 16,480
1 Year Before
Population = 16,480 × 102.5
100
= 16,892
Now,
Present = 16,892 × 105
Population 100