Math, asked by khrawshylla, 11 months ago

The population of a town was 48600 it increased by 25% in the first year and decreased by 8% in the second year. What will be the population of the town at the end of two years?​

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Answered by srb8
1

Answer:

after first year = 48600 + 25% of 48600

=48600+ 48600×25/100

=48600+12150

=60750

after 2nd year = 60750 - 8% of 60750

= 60750 - 60750 ×8/100

=60750 - 4860

= 55890

so, the population after two years is 55890

Answered by vk796049
1

Answer:

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khrawshylla

28.08.2019

Math

Secondary School

+5 pts

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The population of a town was 48600 it increased by 25% in the first year and decreased by 8% in the second year. What will be the population of the town at the end of two years?​

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Answer:

after first year = 48600 + 25% of 48600

=48600+ 48600×25/100

=48600+12150

=60750

after 2nd year = 60750 - 8% of 60750

= 60750 - 60750 ×8/100

=60750 - 4860

= 55890

so, the population after two years is 55890.

I hope this helpful to you.

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