The population of a village decreases at the rate of 20% per annum. If its population 2 years ago was 10000,
what is its present population?
(a) 6000
(b) 10000/144
(c) 6400
(d) 7600
Answers
Answered by
3
"Option C" is the answer - 6400
S = Population after 2 years = ?
i = Annual negative growth rate = 20%
n = Duration = 2 years
R= population at the beginning = 10000
S = R(1+i)^n
= 10000( 1 - 20/100)^2
= 10000( 1 - 0.2)^2
= 10000(0.8)^2
= 10000(0.64)
=6400
R = 6400 = current population
S = Population after 2 years = ?
i = Annual negative growth rate = 20%
n = Duration = 2 years
R= population at the beginning = 10000
S = R(1+i)^n
= 10000( 1 - 20/100)^2
= 10000( 1 - 0.2)^2
= 10000(0.8)^2
= 10000(0.64)
=6400
R = 6400 = current population
Similar questions