Question

The population of a village decreases at the rate of 8% per annum. If its population 3 years ago was 64000000, what is it's approximate present population?​

Answer 1

Answer:

49836032

Step-by-step explanation:

3 Year ago : 64000000

2 year ago : 58880000  (8% Decreased).

1 year ago : 54169600 (8% Decreased again).

now : 49836032 (8% Decreased again).

Answer 2

The approximate present population is 49836032

Solution:

The present population is given as:

$y = a(1-r)^n$

Where,

y is present population

a is the population "n" years ago

r is decreasing rate in decimal

n is number of years

From given,

a = 64000000

n = 3

$r = 8 \% = \frac{8}{100} = 0.08$

Substituting we get,

$y = 64000000 (1 - 0.08)^3 \\\\y = 64000000 \times 0.92^3 \\\\y =64000000 \times 0.778688\\\\y = 49836032$

Thus approximate present population is 49836032

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