Math, asked by geethukp29, 2 months ago

the population of a village grows by r% every year the population increases from 10000 to 11025 then r is​

Answers

Answered by dhivyagovindece
5

Step-by-step explanation:

rate = 5 %.

by using the formula

p=P(1+R/100)^T

Attachments:
Answered by pulakmath007
2

The value of r = 5

Correct question : The population of a village grows by r% every year. In 2 years the population increases from 10000 to 11025. Then r is.

Given :

  • The population of a village grows by r% every year.

  • In 2 years the population increases from 10000 to 11025.

To find :

The value of r

Formula Used :

If Present population is P and Rate of increase in population is r% per annum then Population after n years

 \displaystyle \sf   { A =  P \: {\bigg[1 + \dfrac{r}{100} \bigg]}^{n} \: \: }

Solution :

Step 1 of 2 :

Form the equation to find the value of r

Initial population = P = 10000

Population after 2 years = A = 11025

Rate of increase in population = r%

Number of years = 2

By the given condition

\displaystyle \sf   { A =  P \: {\bigg[1 + \dfrac{r}{100} \bigg]}^{n} \: \: }

\displaystyle \sf{ \implies }11025 =  10000 \times \: {\bigg[1 + \dfrac{r}{100} \bigg]}^{2}

Step 2 of 2 :

Calculate the value of r

\displaystyle \sf  11025 =  10000 \times \: {\bigg[1 + \dfrac{r}{100} \bigg]}^{2}

\displaystyle \sf{ \implies }  {\bigg[1 + \dfrac{r}{100} \bigg]}^{2} =  \frac{11025}{10000}

\displaystyle \sf{ \implies }  {\bigg[1 + \dfrac{r}{100} \bigg]}^{2} =  {\bigg[ \frac{105}{100} \bigg] }^{2}

\displaystyle \sf{ \implies }  {\bigg[1 + \dfrac{r}{100} \bigg]}^{2} =  {\bigg[ 1 + \frac{5}{100} \bigg] }^{2}

\displaystyle \sf{ \implies }  {\bigg[1 + \dfrac{r}{100} \bigg]}^{} =  {\bigg[ 1 + \frac{5}{100} \bigg] }^{}

\displaystyle \sf{ \implies } \dfrac{r}{100}  =   \frac{5}{100}

\displaystyle \sf{ \implies }r = 5

Hence the required value of r = 5

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