Question

The population of a village has a constant growth of 4% every year. If it's present population is 32448. What was the population two years ago?

Answer 1

Answer:

Step-by-step explanation:

a = p(1+r/100)t

= 32448(1+4/100)4

= ur answer

Answer 2

Answer:

The population 2 years ago was 30000.

Step-by-step explanation:

Given:

The rate of growth = 4 %

Present population = 32448

We need to find the population 2 years ago

Let the population 2 years ago be 'x'

We know that if population is increasing, then,

Population after n years = P (1 + $\frac{R}{100}$)ⁿ

where P is the population n years ago

R is the rate of growth of population

and n is the no. of years.

Therefore, on substituting the values,

=> 32448 = x (1 + $\frac{4}{100}$)²

=> 32448 = x (1 + $\frac{1}{25}$)²

=> 32448 = x ( $\frac{26}{25}$)²

=> x = 30000

Therefore, the population 2 years ago was 30000.