The population of a village has a constant growth of 5 % p.a, If its present population is 200,What will be population after 2 years? *
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95,086
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8th
Maths
Comparing Quantities
Applications of Compound Interest
The population of a village...
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The population of a village has a constant growth of 5% every year. If its present population is 1,04,832, what was the population two years ago?
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Let P be the population two years ago.
∴ P(1+
100
5
)
2
=104832
P(
100
105
)
2
=104832
P×
100
105
×
100
105
=104832
P=
105×105
104832×100×100
=95085.71
=95,086 (rounding off to the nearest whole number)
∴ Two years ago the population was 95,086
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