Question

The population of a village is 10,000. The rate of increase of population is 10% annually. The people of the village after 2 years will be
option. a. 11100 b.12100 c. 10100 d.11500

Answer 1

Answer:

Based on how nature works, population will not increase linearly but rather exponentially. Therefore:

Population after two years= 10000(1+0.1)^2=12100 (b)

Hope this helps :)

Step-by-step explanation:

Answer 2

Here your answer✍️

Population of village now➡️10,000
Rate of Increase ➡️10%

For your information Population always increase like Compound interest
So we will use compound interest Formula of finding amount but here Population,

Time➡️2 years
$Population = Population \: now(1 + Rate \: of \: increase \div 100) ^{time} \\ = 10000(1 + \frac{10}{100} ) ^{2} \\ = 10000( \frac{110}{100} ) {}^{2} \\ = 10000 \times \frac{110}{100} \times \frac{110}{100} \\ = 100 \times 11 \times 11 \\ = 12100 \\ Population = 12100$
B.12100