Math, asked by sunilkumar3031998, 10 months ago

the population of a village is 5000 and it increases at yeh rate 2% every year. after 2 years the population will be​

Answers

Answered by Anonymous
28

\huge{\text{\underline{Correct\; Question:-}}}

The population of a town increases every year by 2% of the population at the beginning of that year. The number of year by which year the total increase of population be 40% is

\huge{\text{\underline{Solution:-}}}

Let us assume that the initial population as P

Now after a year population will be:-

\implies P + (2 / 100) P

\implies P (102 / 100)

\implies{\boxed{\text{1.02 P}}}

Similarly after 2 years population will be:-

\implies1.02 x 1.02 x P

So after n number of years population will be:-

\implies{\tt{P x (1.02^n)}}

Point to remember:-

Now this population should be equal to P + 40%

\implies{\tt{1.4 P = P x (1.02^n)}}

\implies{\tt{1.4 = 1.02^n}}

\implies{\tt{1.02^1^7 = 1.02^n}}

\implies\large{\boxed{\text{n = 17}}}

Therefore, after 17 years the total increase in the population will be 40% of that of initial population.

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Answered by Sharad001
67

Question :-

the population of a village is 5000 and it increases at yeh rate 2% every year. after 2 years the population will be..?

Answer :-

→ After two years population is 5202

→ increasing in population after 2 years is 102 .

Formula used :-

 \implies \: P  { \bigg(1 +  \frac{R}{100} \bigg) }^{T}

Step - by - step explanation :-

Given that :-

Assume that,

  • P = 5000

  • R = 2%

  • Time = T

Solution :-

Substitute the given value in the given formula ,

  • Population increase every year ( taken time T = 1)

 \implies \: 5000  { \bigg(1 +  \frac{2}{100} \bigg) }^{1}  \\  \\  \implies \: 5000 \times  \frac{51}{50}    \\   \\  \implies \: 5100

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  • After 2 years ( taken time T = 2)

 \implies \: 5000 { \bigg(1 +  \frac{2}{100} \bigg) }^{2}  \\  \\  \implies \: 5000 \times  \frac{51}{50} \:  \times  \frac{51}{50}   \\  \\  \implies \: 5202

Increase in population after 2 years is ↓

→ 5202 - 5100

→ 102

Therefore ,

Population after 2 years is 5202.

Increase in population after 2 years is 102 .

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