Question

The population of a village is 67000. If it increases 5% and 4%annum respectively in two years find its population after two years

73164 is answer

Answer 1

Given the population is 67000.

First year it will increase 5%.

Increase=5%of 67000

=5/100*67000

=5*670

=3350

The population now becomes 67000+3350

=70350

Next increase =4%

=4/100*70350

=2814

Now the population becomes 70350+2814

=73164

The answer is verified and correct.

Thanks.

Answer 2

$\boxed{\boxed{\boxed{\bold{\green{Solution :\longrightarrow}}}}}$

$\mathfrak{Given,}$

$\bold{Populatio n \: \: of \: \: the \: \: village \: (P) = 67000}$

$\bold{Rate \: \: of \: \: increase \: \: during \: \: {1}^{st} \: \: year = 5\%.}$

$\bold{Rate \: \: of \: \: increase \: \: during \: \: {2}^{nd} \: \: year = 4\%.}$

$\bold{Now}$

$\bold{Population \: \: after \: \: 2 \: \: years}$

$\bold{= p \times (1 + \frac{r}{100} ) \times (1 + \frac{q}{100} ) }\\ \\ \bold{= 67000 \times (1 + \frac{5}{100} ) \times ( 1+ \frac{4}{100} )} \\ \\ \bold{= 67000 \times \frac{105}{100} \times \frac{104}{100}} \\ \\ \bold{= 73164} \: \: \:\boxed{\boxed{\boxed{\bold{\pink{ Ans}}}}}$

$\boxed{\boxed{\boxed{\bold{\red{I \: \: hope \: \: it \: \: will \: \: help \: \: you.}}}}}$