the population of a village was 8400 if the males and female arre increased by 9% and 5% then population will become 8936 after 1 year find the difference between number of males and females at present
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Answered by
0
Step-by-step explanation:
Suppose the number of males in the village before increases was x.
Then, the number of females =(9800−x)
Given, (x+8% of x)+(9800−x)+5% of (9800−x)=10458
⇒1.08x+1.05×(9800−x)=10458
⇒1.08x+1.05×9800−1.05x=10458
⇒0.03x=10458−10290=168
⇒x=
3
168×100
=5600
sahu74824:
wrong
Answered by
0
Step-by-step explanation:
Let the number of males = x
so females= 8400-x
After the increase...
Males = x + x(9/100) = 109x/100
Females = 105/100(8400-x)
=8820-(105x/100)
According to question
= 109x/100 + 8820-(105x/100) = 8936
= 4x/100 =8936-8820
= x = 2900
so Males =2900
Females = 8400-2900
= 5500
Difference between males and females
= 5500-2900
= 2600 Answer.
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