the population of a village when increased by 15% become 19320. what was the original population
Answers
Answered by
29
Let the population = 100
After increasing 15% = 100+15 = 115 .
Now ,
If the increased population is 115 then the original population = 100
If the increased population is 1 then the original population = 100/115
If the increased population is 19320 then the original population =

The original population was 16800.
#Be Brainly !!
After increasing 15% = 100+15 = 115 .
Now ,
If the increased population is 115 then the original population = 100
If the increased population is 1 then the original population = 100/115
If the increased population is 19320 then the original population =
The original population was 16800.
#Be Brainly !!
santramyadav95599417:
Thanks again
Answered by
10
Solutions :-
Given :
the population of a village when increased by 15% become 19320.
Let the original population of village be x
A/q
=> x = 19320 - 15% of x
=> x = 19320 - 0.15 × x
=> x = 19320 - 0.15x
=> x + 0.15x = 19320
=> 1.15x = 19320
=> x = 19320/1.15 = 16800
Hence,
The original population of the village is 16800.
Given :
the population of a village when increased by 15% become 19320.
Let the original population of village be x
A/q
=> x = 19320 - 15% of x
=> x = 19320 - 0.15 × x
=> x = 19320 - 0.15x
=> x + 0.15x = 19320
=> 1.15x = 19320
=> x = 19320/1.15 = 16800
Hence,
The original population of the village is 16800.
Similar questions