Question

The population of Alberta was 1,265,572 in1960. If the population was 3,520,268 in 2009, by what percent did this increase or decrease?

Answer 1

100% 1,265,572. in 1960
X%. 3,520,268. in 2009
X=100•3,520,268/1,265,572
X=278.15%
278.15-100=178.15
Population increased by 178% from 1960 to 2009.

Answer 2

Answer:

178.16%

Step-by-step explanation:

Change = final - initial

=> 3,520,268 - 1,265,572

=> 2,254,696

As change is positive, population is increased

% of population increase = $\frac{2,254,696}{1,265,572} \times 100 = 178.16 \%$

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