The population of certain co7ntry is 80,000,000. With growth rate of 2%. What will be the population number after 10 years
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Answer:
Given present population =142560
Increase in population annually =8%
Present population =
100
x(100+increaseinpopulation)
where x is population last year
∴142560=
100
x(100+8)
⇒x=132000
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