Question

the population of certain town was 500000.in a year male population increase 5%and female population increase 3%.now the population became52020.then what was the number of male and femle in previous year​

Answer 1

Answer:

Male population =x

Female population=y

x+y=50,000

y=50,000−x

x increased 5%

y increased 8%

(x+x×5%)+(y+y×8%)=53220

x+

100

5x

+y+

100

8y

=53220

100x+5x+100y+8y=5322000

as y=50,000−x

100x+5x+108(50,000−x)=5322000

105x−108x+5400000=5322000

5400000−5322000=3x

78000=3x

x=26000

y=50,000−x=50,000−26000

y=24000

∴ Male population=26000

Female population=24000

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

26000 is ans pls like ifts corect