Question

The population of cities A and B is equal. The population of city A increases in two successive years by
20% and 15% respectively and that of city B increases successively by 20% and 10% respectively. If
the difference in the population of two cities after 2 years is 768, then what was the total population of
the two cities initially?​

Answer 1

Answer:

City A = 76.8 city B= 76.8

Step-by-step explanation:

Population of city A be x

population of city b be y

population of city A after 2 year = x135÷100

population of city B after 2 year= y130÷100

if difference is 768

x135÷100-y130÷100= 768

5xy=768

768÷5= 153.6

If two cities were equal in 2 years back

then

2xy= 153.6

xy= 153.6÷2

xy=76.8

if two cities are equal then

x=76.8

y=76.8

POPULATION OF CITY A BACK THEN WAS =76.8

POPULATION OF CITY B BACK THEN WAS =76.8