Question

The population of devgaon increases by 6.25% every year.two years ago,if it was 2560.what is it now?

Answer 1

Answer:

2890

Step-by-step explanation:

The population at time after t years is given by

$P_{t}=P_{0} *(1+\frac{Rate}{100})^t$

where $P_{t}$ is the Population size after t years and $P_{0}$ is the initial population size.

Then, the current population is given as

$P_{2}= 2560*(1+\frac{6.25}{100}) ^{2} \\ P_{2} =2890$