Question

the population of
different trees in a field increased by 10 % in first year, increased by 8 % in
second year and decreased by 10 % in third year. If at present the number of trees is 26730
then find the number of trees in the beginning.
a. 30000
b. 25000
c. 27000
d. 27865
e. None of these​

Answer 1

Answer:

25000

Step-by-step explanation:

equivalent rate = 18.8 -10 +(18.8)(-10)/100= 6.92% (+ve means increase)

106.92% = 26730

100%=25000( in beginning)

option (b) is correct

Answer 2

The number of trees in the beginning is 25000.

Step-by-step explanation:

Since we have given that

First increased by 10%.

Second increased by 8%.

Third decreased by 10%.

Present number of trees = 26730

According to question, we get that

$26730=x(1+\dfrac{10}{100})(1+\dfrac{8}{100})(1-\dfrac{10}{100})\\\\26730=x\dfrac{110}{100}\times \dfrac{108}{100}\times \dfrac{90}{100}\\\\26730=x\times 1.1\times 1.08\times 0.9\\\\\dfrac{26730}{1.0692}=x\\\\x=25000$

Hence, the number of trees in the beginning is 25000.

Therefore, Option 'b' is correct.

# learn more:

The population of a town three years ago was 25000. If it increases at 10%, 15% and 8% in consecutive

three years find the present population,

https://brainly.in/question/14499887