Math, asked by svjqueen, 4 months ago

The population of Morgaon increases by 10% per year. If the population this year
is 2420. what was the population of Morgaon 2 years ago ?
(4) 1936
1) 3000 (2) 2178 181 2000
pls answer fast
don't give useless answers​

Answers

Answered by muskanperween225
3

Step-by-step explanation:

Let the population of Morgaon 2 years ago be 'x'.

Present population of this city =

 = x( {1 +  \frac{10}{100} )}^{2}

 = x( { \frac{100 + 10}{100}) }^{2}

 = x \times  \frac{110}{100}  \times  \frac{110}{100}

 =  \frac{121x}{100}

According to the question,

 \frac{121x}{100}  = 2420

 =  > 121x = 242000

 =  > x =  \frac{242000}{121}

 =  > x = 2000

Answer:- Population of Margaon city 2 years before is 2000.

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