Math, asked by hvlatha1987, 3 days ago

the population of the city increase dy 10 percent every years at present the population of the city is 36,3000 what was the population of the city 2 years ago?​

Answers

Answered by Anonymous
3

Answer:

294,030

Step-by-step explanation:

Present population of the city =  36,3000

As population increases 10% every year

so population 2 years ago =

P(1 - R/100)^2 =  36,3000(1- 10/100)^2 = 294,030

Population 2 years ago was  294,030

Hope you liked the solution. Please mark me as brainliest

Similar questions