Question

the population of the city increase each year by 4℅of what it had been at the beginning of each year if it's present population is 6760000 find its population 2 year ago​

Answer 1

Answer:

this could be solved by two methods

1 by compound interest formulae

2 by percentage

Step-by-step explanation:

for easy understanding by percentage is given

LET THE INTIAL POPULATION TWO YEARS AGO BE     X

THEN

population after one year=

x+ 4%ofx=  104x/100

population after another one year=

104x/100 .   + .   4%of104x/100 .= .   x  ×(104/100)²

but according to question population after two years is  6760000

therefore

x  ×(104/100)²=6760000

on solving for x,we get

x=6250000

hence population two years ago was 6250000

Answer 2

Answer:

Step-by-step explanation:

RATE OF INCREASE=4%

PRESENT POPULATION=6760000                                                                                         LET THE BEGINNING POPULATION =x                                                                              2 YEARS AGO=V=Vo(1+R/100)T                                       HERE-V=6760000                                                         6760000=x(1+4/100)Sq                                                                    Vo=x                              6760000=x(26/25*26*25)                                                                                                         6760000 * 25/26*25/26=x                                                                                                    6760000*625/676=x                                                                                                           10000*625=x                                                                                                                                              6250000=x                                                                                                                              THANK YOU AND PLZ MARK IT AS THE BRAINLIEST