Math, asked by pkiaf65, 11 months ago

the population of the town increase to 84000 in
2010 at rate of 6%per annum find
the population in 2008
the population is 2014​

Answers

Answered by ra9825383209
17

Answer:

population increase by 85000 in 2010

R=6

2010 - 2008

T = 2years

SI = PRT

100

= 85000×6×2

100

= 850×12

= 10200

population in 2008 is

85000-10200

74800

in 2014

2010-2014

4years

SI=PRT

100

=85000×6×4

100

=20400

population in 2014 is

85000+20400

95400

Answered by yj44201229
2

Answer:

hiii

Step-by-step explanation:

you are bedt you can solve foy you

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