Question

the population of the town increased by 10% annually if the present population is 22000 find its population a year ago
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Answer 1

Given that the present population of the town is 22000

The population of the town increased by 10%

We have to find the population of the town a year ago

So let the population of town a year ago be 'A'

We will find 110% of x because in order to find percentage increase

(100+x)/100 where x is the percentage increase in population.

A × (100×10)/100 =22000

A × 110/100 = 22000

A= (22000× 100) /110

A= 20000

Hence the population of the town a year ago was 20000.

Thanks

Answer 2

Answer:

let present population be p

then , p= 22,000

incease in population annually = 10% = 10/100 × p = p/10

10% of p = 1/10 × 22,000 = 2,200

population a year ago = p - 10% of p

                                   = 22,000 - 2,200

                                   = 19,800

ans - the population of the town was 19,800 a year ago.

Step-by-step explanation:

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