Question

The population of the town increases 4% annually if the present population is 54080 what was the population 2 years ago

Answer 1

Answer:

The population two years ago was 50,000

Step-by-step explanation:

This is a case of compounding growth. We can therefore use the expressions of compound interest.

P = initial population = ?

R = rate of growth per cent per year = 4

T = time period in years = 2

A = final population at the end of T years = 54080

A = P(1 + R/100)^T

According to given values,

54080 = P(1 + 4/100)^2

54080 = P*(1.04)²

54080 = P*(1.0816)

P = 54080/1.0816

P = 50000

Original population (two years ago) was 50,000