Question

The population of town in 2005 was 1800000 and in 2006 it become 2100000• find the percentage increase in population•

Answer 1

Step-by-step explanation:

% increase in population=300000/1800000×100=3/18×100=50/3=16.67%

Answer 2

The percentage increase would be 16.67%

Step-by-step explanation:

Given,

The population in 2005 = 1800000,

While, the population in 2006 = 2100000,

Thus, the percentage increase in population

$=\frac{\text{Population in 2006-population in 2005}}{\text{Population in 2005}}\times 100$

$=\frac{2100000-1800000}{1800000}\times 100$

$=\frac{300000}{1800000}\times 100$

$=\frac{1}{6}\times 100$

≈ 16.67%

#Learn more :

Find the percentage change in each case ​:

https://brainly.in/question/12416585