Math, asked by donthakur, 1 year ago

The population of town in 2010 was 1800000 and in 2011 it was 2100000. Find the increased percent ?

Answers

Answered by 1helpingbuddy
16
increase in population=2100000-1800000=30000
increase percent= 30000/2100000×100%
=10/7
=1.43%

donthakur: your answer is wrong
donthakur: totally wrong answer
1helpingbuddy: sorry bro.
Answered by Sizzu
5

Answer:

Step-by-step explanation: increase in population =2100000-1800000

=300000

Increase percent of the population of the city=(300000/1800000)×100=16.6666%

=16.67%

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