Question

the population of town increases by 20% every year If the present population is 84000 What was it a year ago

Answer 1

Answer:

Step-by-step explanation:

Because

A=p(1+r/100)^n

Where

P=p

R=20%p.a=20/100p.a

T(n)= 1 yr

& A=84,000

Hence

84,000=p(1+20/100)^1

84,000=p(6/5)

P=84,000*5/6

P=70,000

Hence , population of the town a year ago was 70,000

Answer 2

$\bold{\underline{Question:}}$

The population of town increases by 20% every year. If the present population is 84000. What was it 1 year ago?

$\bold{\underline{Solution:}}$

$\bold{\textsf{Let the no. of population 1 year ago be x.}}$

Given in the question ,

• The population increases 20% every year.
• The present population = 84000.

According to question ,

$\implies{\bold{\textsf{x of (100+20)\% = 84000}}}\\\\\\\implies{\bold{x*\frac{120}{100}=84000}}\\\\\\\implies{\bold{x=84000*\frac{100}{120}}}\\\\\implies{\bold{x=70000.}}\\\\\\\bold{\boxed{\textsf{A year ago population = x = 70000.}}}$