Question

the population of town is 176400. If it increases at the rate of 5% per annum,what will be its population 2 years hence

Answer 1

Here is your answer..

Answer 2

Here, the population increases compounded annually.

P = 176400

r = 5

n = 2

$A = P(1 + \frac{r}{100})^n$

$= 176400 * (1 + \frac{5}{100})^2 \\ \\ = 176400 * (\frac{105}{100})^2 \\ \\ = 176400 * \frac{105}{100} * \frac{105}{100} \\ \\ = \frac{1764 * 105^2}{100} \\ \\ = \frac{42^2 * 105^2}{10^2} = (\frac{42 * 105}{10})^2 = 441^2 = 194481$

194481 is the answer.

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