Question

the population of town is 8000. it increases by 10% during first year and by 20% during second year. find the population after 2 years.

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Answer 1

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Answer 2

The population after 2 years is 10560

Step-by-step explanation:

Present population of town is 8000

We are given that  it increases by 10% during first year

So, Population after 1 year = $8000+10\% \times 8000=8000+\frac{10}{100} \times 8000=8800$

We are given that it increases by 20% during second year.

So, Population after second year = $8800 + 20\% \times 8800 = 8800+\frac{20}{100} \times 8800=10560$

Hence the population after 2 years is 10560

#Learn more:

The population of town increase by 5% every year. if the present population is 5400000.find the population after 2 years

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