Question

The population of town is increased from 54500 to 58500 in one year what is the percentage increase in the population?

Answer 1

Answer:

7.34% increase

Explanation:

58500-54500= 4000

increase = (4000/54500)*100

=7.339% which is approximately equal to 7.34%

Answer 2

Given,

The population of town is increased from 54500 to 58500 in one year.

To find,

The percentage increase in the population.

Solution,

We can simply solve this mathematical problem using the following process:

Mathematically,

Percentage increase

= (increase in initial value)/(initial value) × 100

{Statement-1}

Now, according to the question;

The initial population of the town = 54500

The final population of the town after one year

= 58500

The increase in the population of the town

= (final population of the town) - (initial population of the town)

= 58500 - 54500 = 4000

Now, according to the question;

The percentage increase in the population

= (increase in initial value)/(initial value) × 100

= (increase in the population of the town)/(initial population of the town) × 100

{according to statement-1}

= (4000)/(54500) × 100

= 7.34%

Hence, the percentage increase in the population of the town is approximately 7.34%.