The populaton is a town is 12000and it increase at the rate of 10 percent per annum.find thd population of this town after 3year
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initial=12000
rate of change=10%
so final = 12000×110/100×110/100×110/100
=15972
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Answer:
15972
Step-by-step explanation:
1. So the initial population is 12000 and it increased 10 percent n 1st year so
10 percent of 12000 is 1200
so population in first year is 13200
2. so in 2nd year population is again 10 percent of previus year i.e.
10 percent of 13200 i.e. 1320
so population in 2nd year is 13200+1320 = 14520
3. so population in 3rd year is also 10 percent of previous year i.e.
10 percent of 14520 = 1452
so population in 3rd year is 14520 + 1452 = 15972
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