Question

The position coardinate of a projectile projected from ground on a certain planet (with no atomsphere) are given by y=[4t-2t^2] m and x= (3t)metre , where t is in second and point of projection with vertical is...........


Plzzzz explain in detail step by step. .....I Will make brainlist

Answer 1

Velocity can be found by differentiating these terms.

Vy=4-4t

Vx=3

Now, for initial velocity, t=0. So velocity in y would be 4.

We know that Vy/Vx=tan theta.

So, angle=tan-14/3