Physics, asked by rachitlund7858, 9 months ago

The position coordinate of a moving particle is given by x = 6 + 18t + 9t2. (where x in meters and t in seconds). What is its velocity and acceleration at t = 2 sec.?

Answers

Answered by mk6890227

2

Answer 54

Explanation:x=6+18t+9t^2

Now differentiate it to find velocity

V=18 +18t

t=2 given

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