Question

the position coordinate of moving particle along x axis is given by x=9+18t+9t^2 (where x is in meter, t in second). what is its position, velocity and acceleration at t=2s

Answer 1

Don't know

Sorry sorry

Answer 2

DX/dt gives the velocity so we get 18+18t and at t=2 sec se get velocity is 54 m/s and again differentiating it we get 18 metre per second square which is the acceleration hope it helps