the position coordinate of moving particle along x axis is given by x=9+18t+9t^2 (where x is in meter, t in second). what is its position, velocity and acceleration at t=2s
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Don't know
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DX/dt gives the velocity so we get 18+18t and at t=2 sec se get velocity is 54 m/s and again differentiating it we get 18 metre per second square which is the acceleration hope it helps
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