Question

The position coordinates of a particle moving in 3d

Answer 1

• The speed of the particle is $\sqrt{2}$ aw.

Given-

The position coordinates of a particle moving in a 3-D coordinate system is -

• x = a cos ωt
• y = a sin ωt
• z = aωt

Position vector of any particle in 3 d can be given by

r vector = x i + y j + z k

So magnitude of r vector is = (x² + y² + z² )^1/2

So magnitude of V can be given by = (V² x + V² y + V² z)^1/2

By putting the values of Vx, Vy and Vz we get

V = (a²ω² + a²ω²)^1/2

V = $\sqrt{2}$aw

Answer 2

Explanation:

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