Question

The position coordinates of a projectile thrown from ground are given by y = 3t – 5t2 (m) and x = 4t (m) (here t is in second, x is horizontal and y is vertical position). horizontal range of the projectile is

Answer 1

Answer:

Explanation:

Simply, first put y=0 to find time. And then differentiate y and x individually to get velocity in y and x direction respectively . Then find net velocity by sum of v(x) and v(y) and their square root. Answer is 5.

Answer 2

Answer:

Hey dear hear is your answer

Explanation:

Click on the upper picture