the Position depends on force f=7-2x+3xsqure Newtown acts on the small body and displaces for x1=0 metere to x2=5metere calculate the work done
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Explanation:
Given that,
Force F=7−2x+3x2
We know that,
F=dxdw
dw=Fdx
Now, the work done is
∫dw=0∫5F⋅dx
∫dw=0∫5(7−2x+3x2)dx
W=[7x−22x2+33x3]05
W=35−25+125
W=135J
Hence, the work done is 135 J
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