the position of a body change by given equation x=t(t-1) find 1.velocity when Displacement is 0 2.distance and displacement travelled by body in t=2sec 3.v-t and speed time
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Answer:
5 m
Explanation:
Given,
x=t 2−4t+6
So, the change in velocity is:
dt dx=2t−4
Since velocity is changing,
At t=0,x1=6
At t=2,x2=2
So the magnitude of the distance traveled is:
6−2=4m
At t=3,x3=3
So distance traveled from t=2s to t=3s
x3−x2=3−2=1m
Thus the total distance is:
4+1=5m
Hope this answer helps you
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