the position of a body is given by x= ( 3t⁴ + 4t³ + 2t² + 5t + 1 ) m/s. find velocity at t = 3 seconds. find acceleration at t = 4seconds
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Answer:
Given displacement x=5+3t+2t
2
Differentiating the above equation with respect to time t we get velocity of the body
v=
dt
dx
=3+4t
Now again differentiating the velocity with respect to time we get acceleration
a=
dt
dv
=4
Explanation:
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Answered by
0
Answer:
The position of a body is given by x= ( 3t⁴ + 4t³ + 2t² + 5t + 1 ) m/s.
The velocity at t = 3 seconds will be and
Acceleration at t = 4seconds will be
Explanation:
- The velocity can be defined as the rate of change of position with respect to time and
- in the same way, acceleration can be defined as the rate of change of velocity or the second derivative of position with respect to time.
- Let x be the position, v be the velocity and a be the acceleration of an object.
Then, by definition,
and
- In the question, it is given that,
- Taking the derivative of x,
put
- Taking the derivative of v
put to obtain acceleration at t=4s
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