Question

The position of a body moving along x-axis as a
function of time t is given as x = t ^2- 2t metre. The
distance travelled by the body in first two seconds
is
(1) Zero
(2) 1 m
(3) 2 m
(4) 4 m​

Answer 1

Answer:

Position of body at-

(a) 0 seconds

= 0×0 - 2×0 = 0 m

(b) 2 seconds

= 2×2 - 2×2 = 0 m

Distance travelled

= Change in position

= 0-0 = 0 m (1)

PLEASE MARK IT AS BRAINLIEST ANSWER!!!!!!!

Answer 2

Answer:

2 meters.

Explanation:

Given equation is:

$x=t^2-2t$

Comparing with s=ut+1/2 at²,

$</p><p>u=-2\\</p><p>a=2$

Now, $v=u+at\\</p><p>v=0\implies \: -2+2(t)=0\\</p><p>\implies t=1\\</p><p>\text{Body stops at t=1 sec.}\\</p><p>s=(1)^2-2(1)=-1\\</p><p>\text{Body travels 1 metre before stopping and reversing its direction.}\\</p><p>\text{It travels another 1 metre back to}\\ \text{its starting point.}$

Hence, total distance travelled is 1+1=2metres, but displacement is (1-1)=0metres.