the position of a body of mass 1 kg varies accoding to the law x(t)=At+Bt^2,where A=5 m/s and B=2 m/s^2 . the force acting on the body at t=2 second is.
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F = ma
For finding a we have to double differentiate of x wrt time
dxdt =v = A + 2Bt
dv/dt = a = 2B = 2*2 =4m/s^2
Now F =m*a = 1*2 =2N
For finding a we have to double differentiate of x wrt time
dxdt =v = A + 2Bt
dv/dt = a = 2B = 2*2 =4m/s^2
Now F =m*a = 1*2 =2N
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